| |
|
| KU Interactive Mathematics |
|
|
| Help Files |
Powers of i
| Question: How do we approach problems such as i 1987? |
Yours
Truly answers: When i is raised to a large power such as 1987, we want to use i 4 = 1.
This is because i 4 = (i 2)2 = (–1)2 = 1. Begin by dividing the power 1987 by 4. Then,
Therefore, 1987 = 4·496 + 3. We now use some properties of exponents reviewed in Charpter R.
i 1987 = i 4·496+3 = (i 4·496)(i 3) = (i 4)496(i 3) = (1)496(i 2·i ) = 1·((–1)·i ) = – i
|
|
| |
| Help Files |
|
| KU Interactive Mathematics |
|
Disclaimer Updated
September 4, 2008
|
|